-x+4=-x^2/4+10

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Solution for -x+4=-x^2/4+10 equation: 


x in (-oo:+oo)

4-x = ((-x)^2)/4+10 // - ((-x)^2)/4+10

4-(((-x)^2)/4)-x-10 = 0

(-1/4)*x^2-x-10+4 = 0

-1/4*x^2-x-6 = 0

DELTA = (-1)^2-(-6*(-1/4)*4)

DELTA = -5

DELTA < 0

x belongs to the empty set

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